初一初一下册数学因式分解填空题

初一因式分解练习题
初一因式分解练习题
1)a的四次方+a²+1=a^4+2a²+1-a²=(a²+1)²-a²=(a²+a+1)(a²-a+1)(2)2a²-7ab+6b² =(2a-3b)(a-2b)(3)3x²+xy-2y² =(3x-2y)(x+y)(4)10a²b²+11ab-6 =(2ab+3)(5ab-2)(5)7a³x-28a(x的五次方)=7a³(x-4a²)(6)x³-10x²+16x=x(x²-10x+16)=x(x-2)(x-8)(7)(x²+3x)²-2(x²+3x)-8=(x²+3x+2)(x²+3x-4)=(x+1)(x+2)(x+4)(x-1)(8)(x-y)²+4xy-1 =x²-2xy+y²+4xy-1=x²+2xy+y²-1=(x+y)²-1=(x+y+1)(x+y-1)9.x^2 -4xy +4y^2 -x +2y -2= (x-2y)^2 - (x-2y) -2=(x-2y + 1)(x-2y-2)10.x³+ax²+bx²+cx²+abx+bcx+acx+ab=x³+cx²+abx+abc+bx²+bcx+ax²+acx=x²(x+c)+ab(x+c)+bx(x+c)+ax(x+c)=(x+c)[x²+bx+ab+ax]=(x+c)[x(x+b)+a(x+b)]=(x+a)(x+b)(x+c)11.x²-y²-y-1/2=x²-(y²+y+1/4)=x²-(y+1/2)²=(x+y+1/2)(x-y-1/2)12.x的四次方+3x³+6x ² -4=x^4+x³+2x³+2x²+4(x²-1)=x³(x+1)+2x²(x+1)+(4x-4)(x+1)=(x+1)(x³+2x²+4x-4)13.x³-3x²+4=x³+1-3(x²-1)=(x+1)(x²-x+1)-(3x-3)(x+1)=(x+1)(x²-4x+4)=(x+1)(x-2)²14.32a[(x^2+2x)^2]-2a =2a[16(x^2+2x)^2-1] =2a(4x^2+8x+1)(4x^2+8x-1) 15.16+8(x^2+4x)+(x^2+4x)^2 =(4+x^2+4x)^2 =(x^2+4x+4)^2 =(x+2)^4 16.3x^ny+9x^(n-1)y^2+x^(n+1)/4 =x^(n-1)(3xy+9y^2+x^2/4) =x^(n-1)(x^2/4+3xy+9y^2) =x^(n-1)(x/2+3y)^2 =(1/4)[x^(n-1)](x+6y)^217.a^4+a³+3a-5=a²*(a²+a)+3a-5 =3a²+3a-5 =3(a²+a)-518.1+x+x(x+1)+x(x+1)^2+x(x+1)^3 =(1+x)+x(x+1)+x(x+1)^2+x(x+1)^3 =(1+x)(1+x)+x(x+1)^2+x(x+1)^3 =(1+x)²(1+x)+x(x+1)^3 =(1+x)³(1+x)=(1+x)^419. (x-y)(2x-2y-3)-2
=(x-y)[2(x-y)-3]-2
=2(x-y) ^2-3(x-y)-2
=[(x-y)-2][2(x-y)+1]
=(x-y-2)(2x-2y+1). x2-3xy-10y2+x+9y-2=(x-5y+2)(x+2y-1). x2-y2+5x+3y+4=(x+y+1)(x-y+4). xy+y2+x-y-2=(y+1)(x+y-2). 6x2-7xy-3y2-xz+7yz-2z2=(2x-3y+z)(3x+y-2z). a^2+2b^2+3c^2+3aB+4ac+5bc =(a+b+c)(a+2b+3c)x^2-8x+7 =(x-1)(x-7)X^2+8X+7= (x+1)(x+7)X^2-10X-11 =(x-11)(x+1)x^2+10X-11= ,(x+11)(x-1)X^+3x-18 =(x+6)(x-3)x^2+11X+18 =(x+2)(x+9) x^2-11x+18 =(x-2)(x-9) x^2+17X-18 =(x+18)(x-1)X^2-17X-18 =( x-18)(x+1) xy+6-2x-3y=(x-3)(y-2)x2(x-y)+y2(y-x)=(x+y)(x-y)^2 2x2-(a-2b)x-ab=(2x-a)(x+b) a4-9a2b2=a^2(a+3b)(a-3b) x3+3x2-4=(x-1)(x+2)^2 ab(x2-y2)+xy(a2-b2)=(ay+bx)(ax-by) (x+y)(a-b-c)+(x-y)(b+c-a)=2y(a-b-c) a2-a-b2-b=(a+b)(a-b-1) (3a-b)2-4(3a-b)(a+3b)+4(a+3b)2=[3a-b-2(a+3b)]^2=(a-7b)^2 (x+1)2(x+2)-(x+1)(x+2)2=-(x+1)(x+2)abc+ab-4a=a(bc+b-4) 16x2-81=(4x+9)(4x-9) 9x2-30x+25=(3x-5)^2 x2-7x-30=(x-10)(x+3) x2-25=(x+5)(x-5) x2+4x+3=(x+1)(x+3)4x2-12x+5=(2x-1)(2x-5)3ax2-6ax=3ax(x-2) x(x+2)-x=x(x+1) x2-4x-ax+4a=(x-4)(x-a) 25x2-49=(5x-9)(5x+9) 36x2-60x+25=(6x-5)^2 4x2+12x+9=(2x+3)^2 x2-9x+18=(x-3)(x-6) 2x2-5x-3=(x-3)(2x+1) 12x2-50x+8=2(6x-1)(x-4) (x+2)(x-3)+(x+2)(x+4)=(x+2)(2x-1) 2ax2-3x+2ax-3= (x+1)(2ax-3)9x2-66x+121=(3x-11)^2 8-2x2=2(2+x)(2-x) 9x2-30x+25=(3x-5)^2 -20x2+9x+20=(-4x+5)(5x+4) 12x2-29x+15=(4x-3)(3x-5) 36x2+39x+9=3(3x+1)(4x+3) 21x2-31x-22=(21x+11)(x-2) 9x4-35x2-4=(9x^2+1)(x+2)(x-2) (2x+1)(x+1)+(2x+1)(x-3)=2(x-1)(2x+1) 2ax2-3x+2ax-3=(x+1)(2ax-3) x(y+2)-x-y-1=(x-1)(y+1) (x2-3x)+(x-3)2=(x-3)(2x-3) 9x2-66x+121=(3x-11)^2 8-2x2=2(2-x)(2+x) x4-1=(x-1)(x+1)(x^2+1) x2+4x-xy-2y+4=(x+2)(x-y+2) 4x2-12x+5=(2x-1)(2x-5) 21x2-31x-22=(21x+11)(x-2) 4x2+4xy+y2-4x-2y-3=(2x+y-3)(2x+y+1) 9x5-35x3-4x=x(9x^2+1)(x+2)(x-2) 3x2-6x=3x(x-2) 49x2-25=(7x+5)(7x-5) 6x2-13x+5=(2x-1)(3x-5) x2+2-3x=(x-1)(x-2) 12x2-23x-24=(3x-8)(4x+3) (x+6)(x-6)-(x-6)=(x-6)(x+5) 3(x+2)(x-5)-(x+2)(x-3)=2(x-6)(x+2) 9x2+42x+49=(3x+7)^2 . 3a3b2c-6a2b2c2+9ab2c3=3ab^2 c(a^2-2ac+3c^2) xy+6-2x-3y=(x-3)(y-2) x2(x-y)+y2(y-x)=(x+y)(x-y)^2 2x2-(a-2b)x-ab=(2x-a)(x+b) x^3+2x^2-16x-32=(x+2)(x+4)(x-4)(a-b)a^6+(b-a)b^6=(a-b)^2(a^2+ab+b^2)(a+b)(a^2-ab+b^2)(x+y)(x+y+2xy)+(xy+1)(xy-1) =(x+1)(y+1)(x+y+xy-1) X^8+X^7+1 =(X^2+X+1)(X^6-X^4+X^3-X+1) x^8+x^6+x^4+x^2+1 =(x^4+x^3-x+1)(x^4+x^3+x^2+x+1) x^2-20x+100=(x-10)^2x^2-3x+2=(x-1)(x-2)x^2-2x-15=(x+3)(x-5)x^2+2x-15=(x-3)(x+5)x^2-7x+12=(x-3)(x-4)x^2-7x-30=(x+3)(x-10)x^2+2x-3=(x-1)(x+3)x^2-16x+64=(x-8)^2x^2-9x+20=(x-4)(x-5)x^2-6x+8=(x-2)(x-4)x^2-6x-7=(x-7)(x+1)
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与《初一因式分解练习题》相关的作业问题
(1)原式=a(x²+2a+a²)=a(x+a)²(2)原式=3a²(2a - 3)(3)原式=16x²y²z²(1+3x² - 6z²)(4)原式=0,(5)原式=0,(6)原式=2ab(a+b)(2 - 3a)(7)原式=(x
1.(x-1)(x-7)2.(x+1)(x+7)3.(x+1)(x-11)4.无实数解5.(x+11)(x-1)6.(x+6)(x-3)8.(x-9)(x-2)9.(x+18)(x-1)10.(x+1)(x-18)以上均为简单十字相乘11.原式=x(2x-3y-1)12.原式=(x+y)^4(x-y)(y+z)13.原
(1)a的四次方+a²+1=a^4+2a²+1-a²=(a²+1)²-a²=(a²+a+1)(a²-a+1)(2)2a²-7ab+6b² =(2a-3b)(a-2b)(3)3x²+xy-2y² =(3
因式分解3a3b2c-6a2b2c2+9ab2c3=3ab^2 c(a^2-2ac+3c^2) 3.因式分解xy+6-2x-3y=(x-3)(y-2) 4.因式分解x2(x-y)+y2(y-x)=(x+y)(x-y)^2 5.因式分解2x2-(a-2b)x-ab=(2x-a)(x+b) 6.因式分解a4-9a2b2=a
1.m2(p-q)-p+q;2.a(ab+bc+ac)-abc;3.x4-2y4-2x3y+xy3;4.abc(a2+b2+c2)-a3bc+2ab2c2;5.a2(b-c)+b2(c-a)+c2(a-b);6.(x2-2x)2+2x(x-2)+1;7.(x-y)2+12(y-x)z+36z2;8.x2-4ax+8ab
这是初一因式分解练习题的截图给个邮箱地址,我把练习题文件直接发给你 再问: 谢谢
1、原式=3x~-3xy-x~-x=3x(x-y)-x(x+1)=x(3x-3y-x-1)=x(2x-3y-1)3、原式=3x(a+2b)~-6xy(a+2b)=3x(a+2b)(a+2b-2y)4、原式=(a-b+c)(x-y)5、原式=(b-a)(b-a+2)6、原式=(x-y)(x-y-m+1)7、原式=(x-y
(3m+n+1)·(3m-n)
^2(x-3)+(3-x)=b^2(x-3)-(x-3)=(b^2-1)(x-3)=(b+1)(b-1)(x-3)
1,(x-1)(x-7)2,(x+1)(x+7)3,(x-11)(x+1)4,无解5,(x+11)(x-1)6,(x+6)(x-3)7,(x+2)(x+9)8,(x-2)(x-9)9,(x+18)(x-1)10,(x-18)(x+1)
x^2 -4xy +4y^2 -x +2y -2= (x-2y)^2 - (x-2y) -2=(x-2y + 1)(x-2y-2)
习题带答案的在下面
想要课后题答案就去书店买完全解读或者王后雄的参考书我觉的你还是自己买一本,靠网上找的题太少了
题在哪? 再问: 你们帮我找题,我做。。。。。。。O(∩_∩)O~ 再答: 额额额额额额额额额额额额,我去看看,我去找找先。。。。 (x+2)(x-3)+(x+2)(x+4)=再问: 好吧(∩_∩) 再答: 2ax2-3x+2ax-3= 9x2-66x+121= 8-2x2= x2-x+14 = 9x2-30x+25=
x^2-3x+2=(x-2)(x-1)x^4+2x^3-x^2-2x=x^3(x+2)-x(x+2)=(x+2)(x^3-x)=x(x+2)(x^2-1)=x(x+2)(x-1)(x+1)4x^2-9y^2=(2x+3y)(2x-3y)
http://wenku.baidu.com/view/ea09.html
1.(X+Y)(X+Y+2XY)+(XY+1)XY-1)2.X^2-Y^2-2X-4Y-33.(XY-1)^2+(X+Y-2)(X+Y-2XY)4.X^4(Y^2-Z^2)+Y^4(Z^2-X^2)+Z^4(X^2-Y^2)5.a^3*x^2n+1+8a^2*x^2n+5+16ax^2n+96.ab(a+b)^2-(a
-a^3-4a²+12a=-a(a²+4a-12)=-a(a+6)(a-2)初一年级因式分解练习题_百度文库
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==================资料简介======================一、选择题(本题有10小题,每小题3分,共30分)1. 利用因式分解计算2,则结果是(
D.-12. 下列多项式中,不能运用平方差公式因式分解的是(
)A.-m2+4
B.-x2-y2
C.x2y2-1
D.(m-a)2-(m+a)23. 因式分解(x-1)2-9的结果是(
)A.(x+8)(x+1)
B.(x+2)(x-4)
C.(x-2)(x+4)
D.(x-10)(x+8)4. 把代数式3x3-6x2y+3xy2分解因式,结果正确的是(
)A.x(3x+y)(x-3y) B.3x(x2-2xy+y2) C.x(3x-y)2
D.3x(x-y)25. 下列因式分解错误的是(
)A.x2-y2=(x+y)(x-y)
B.x2+6x+9=(x+3)2C.x2+xy=x(x+y)
D.x2+y2=(x+y)2================================================压缩包内容:浙教版初中数学七年级下因式分解单元练习(答案).doc浙教版初中数学七年级下因式分解单元练习.docx
试卷类型:单元测试
资料版本:浙教版
适用地区:浙江省
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