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设A是s×n 矩阵(s≠n),则以下关于矩阵A的叙述正确的是( A.ATA是s×s对称矩阵\x05B.ATA=AATC.(ATA)T =AAT\x05D.AAT是s×s对称矩阵
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A肯定错因该是nxn的;B也不对,没有交换律;C也不对ATA是nxn的、转置矩阵也是,但AAT是sxs的;选D,抱歉我不知道什么是对称矩阵,还没有学到.
AT=A,是对称矩阵
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其他类似问题
A 是 sxn则
A^T 是 nxs所以 AA^T 是 sxs故 (D) 正确.
怎么不是A,
A^T 是 nxs
A^TA 是 nxn 而不是 sxs
结果就是 1x1, 看作一个数.
A是 mxs, B是sxn , 则 A,B 可乘, 且乘积为 mxn 矩阵.
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