matlab怎么求开matlab求平方根函数的积分,对于例子i

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matlab中编写开平方根怎么编写啊?比如a=c*d+e;k=g*d+f*s;求开平方eqrt(a^2+k^2)
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syms c d e f g sa=c*d+e;k=g*d+f*s;yy=sqrt(a^2+k^2)
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matlab怎么求开平方根的积分,对于例子int(sqrt(r^2-((x-R*cos(a))/(cos(a)))^2),x,2*R*cos(a)/(cos(a)+1),(R+r)*cos(a)):出现int((r^2 - (x - R*cos(a))^2/cos(a)^2)^(1/2), x = (2*R*cos(a))/(cos(a) + 1)..cos(a)*(R + r))对于int(r^2-((x-R*cos(a))/(cos(a)))^2,x,2*R*cos(a)/(cos(a)+1),(R+r)*cos(a))结果为(cos(a)*(r - R + R*cos(a) + r*cos(a))^2*(R + 2*r - R*cos(a) + 2*r*cos(a)))/(3*(cos(a) + 1)^3),这是为什我知道了,代码如下,先解方程再进行代入就行了,由于迭代次数的问题,cos对于这个过程可能是系统的漏洞,一下就进入漏洞了,因此这个解决的方法clearsyms R r x by ty a ty1 ty2 ty3 ty1=int((r^2-(x-R*cos(a))^2/(cos(a))^(1/2)));ty2=subs(ty1,'x','2*R*cos(a)/(cos(a)+1)');ty3=subs(ty1,'x','(R+r)*cos(a)');ty=ty3-ty2;ty = r^2*cos(a)*(R + r) - (cos(a)*(R + r) - R*cos(a))^3/(3*cos(a)^(1/2)) - (R*cos(a) - (2*R*cos(a))/(cos(a) + 1))^3/(3*cos(a)^(1/2)) - (2*R*r^2*cos(a))/(cos(a) + 1)
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int函数是符号积分,求出的是显式表达式,如果只求数值的话推荐使用数值积分参考:http://sunxiaojun3312./blog/static/43/
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