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如何用多个矩形框圈出图像中多个对象
<h1 style="color:# 麦片财富积分
新手, 积分 5, 距离下一级还需 45 积分
关注者： 1
根据第二个附件的数据（可以通过b=dlmread('duiying.txt');转化为矩阵，然后查看相应图像），用矩形框圈出第一个附件中图片的对应部分（也就是两个人）~~
不知道我有没有说清楚~~
想了一下午了，还没想通，因为要圈两个人，所以一直有点纠结，还请高手指教啊，大家都来讨论下啊~~急~~
谢谢谢谢~~
20:53 上传
点击文件名下载附件
494.13 KB, 下载次数: 1406
关注者： 57
两个人和一个人没区别&&你只要能识别出来两个人就可以了
[color=red][size=5][b]相互学习共同进步 若帮到你请给威望和评分[/b][/size] [/color]
<h1 style="color:# 麦片财富积分
关注者： 1
没有区别啊？
因为我是要计算机自己去识别的，没有人为的干预，所以我想根据附件中的第二个图的相应特征，在第一个附件的图中圈出来~~
两个人的话要定8个坐标点，而且如果程序要通用的话，比如更多的人，具体坐标又要怎么确定呢？
<h1 style="color:#0 麦片财富积分
关注者： 4
把txt内容贴出来,别老上传附件
下载要M币,就没人愿意下载了
<h1 style="color:# 麦片财富积分
关注者： 1
回复 4# libralibra 的帖子
多谢提醒哦，O(∩_∩)O~
把上面的图压缩了下，虽然压缩的已经很小了，还是矩阵有点小大，额~~
附件一图像img矩阵：
img=[121,117,123,125,125,131,125,127,129,126,127,125,124,112,114,116,127,133,138,142,143,143,139,136,130,129,125,123,97,118,118,121,115,116,117,119,120,125,120,124,124,126,123,120,119,107,113,113,125,136,146,151,153,152,148,139,135,128,120,117,95,114,112,118,84,81,86,88,90,95,86,94,90,87,89,90,89,73,78,83,93,101,108,117,115,111,107,104,99,93,90,89,76,82,84,88
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107,108,100,116,131,135,134,140,98,89,125,128,137,105,126,125,124,118,111,89,89,37,28,35,38,49,97,103,117,105,121,124,116,115,103,121,133,135,139,142,46,41,98,103,111,85,128,128,132,128,104,75,75,39,29,35,35,48,93,106,120,107,120,123,82,79,68,85,96,96,99,99,38,30,70,75,80,66,89,87,94,84,76,55,55,32,28,33,36,42,67,71,79,76,85,87
131,123,119,123,133,138,137,137,107,106,136,141,107,96,126,128,122,118,111,120,132,35,35,34,39,68,110,108,115,102,105,105,133,128,122,128,135,142,136,137,47,45,135,140,111,87,131,131,130,126,126,128,132,37,37,37,42,73,112,113,116,108,108,107,96,91,89,92,96,99,100,98,32,33,94,98,74,59,91,90,92,82,97,84,93,34,34,37,31,61,81,77,81,76,78,76
136,129,121,126,132,141,137,30,31,39,135,137,121,116,129,125,126,107,106,110,120,35,34,39,38,57,113,114,105,100,105,120,138,131,119,127,134,138,136,37,35,40,131,133,122,120,129,127,131,113,120,118,129,39,38,39,37,57,116,117,109,106,107,119,101,92,87,92,97,102,101,37,25,35,99,99,87,83,97,88,95,73,87,74,88,36,35,30,31,55,75,76,72,74,76,84
133,127,128,131,128,143,144,34,35,28,143,143,139,113,124,122,123,89,112,108,128,38,31,37,37,81,110,115,112,106,103,102,135,130,130,133,132,145,144,36,32,33,142,142,139,120,128,126,129,100,124,114,130,40,33,41,36,88,115,119,117,108,104,110,98,97,93,94,95,106,105,33,26,27,107,106,100,84,91,89,89,69,87,72,93,35,28,31,37,76,79,82,77,77,77,72
133,129,128,134,125,140,147,109,31,37,58,140,127,106,119,119,124,66,117,86,124,96,115,114,98,109,119,101,98,99,102,121,135,129,128,134,121,140,143,107,33,38,53,139,127,109,123,117,123,77,122,85,121,92,110,101,87,114,118,104,103,101,101,117,96,97,96,95,83,101,107,87,26,33,53,103,95,78,86,85,88,60,86,56,85,66,80,78,70,84,83,74,63,70,72,83
123,120,114,65,46,48,47,42,42,33,34,44,53,41,38,42,118,44,123,56,116,99,109,116,114,108,125,103,103,105,108,126,129,126,116,62,54,53,49,43,41,36,34,49,56,46,40,41,120,57,123,63,119,93,95,103,105,114,125,107,98,110,110,127,87,84,73,50,46,47,42,38,30,29,32,36,45,34,35,36,83,46,84,51,84,65,75,80,77,81,86,74,64,74,79,92
80,80,85,88,89,103,110,115,110,39,120,124,118,108,114,109,118,91,101,53,108,98,114,115,107,114,122,105,92,109,110,127,75,78,82,86,86,98,105,112,106,37,118,118,112,104,104,104,111,86,92,50,101,93,106,104,98,119,120,106,84,112,113,126,45,52,52,54,57,68,71,72,70,35,76,80,74,68,71,70,76,56,64,44,73,69,75,81,75,83,88,77,63,79,80,91
108,115,115,111,115,124,127,116,103,35,122,118,117,114,116,117,115,101,107,98,96,97,109,109,66,115,108,101,98,105,111,122,107,113,114,113,113,120,124,116,85,35,124,116,111,111,115,111,113,104,106,93,93,94,102,96,60,114,109,102,100,112,115,125,71,74,72,74,74,78,84,77,59,26,81,77,73,71,74,73,74,63,70,59,69,70,74,72,40,78,80,73,69,76,82,84
112,113,109,116,109,114,122,121,112,101,116,116,118,114,121,120,121,116,115,107,96,98,107,114,99,106,113,106,95,69,100,123,110,111,110,112,108,115,122,119,103,83,117,116,112,113,116,115,120,112,114,102,91,90,97,100,94,105,109,103,91,68,103,119,71,69,69,74,67,74,77,77,68,61,76,77,68,72,76,75,78,74,69,62,67,65,72,80,60,64,65,63,57,49,70,85
109,107,109,109,113,113,119,116,89,111,114,112,114,109,119,123,118,118,118,111,97,91,104,110,107,110,104,98,99,103,113,115,108,103,105,107,107,111,118,110,81,107,107,107,110,106,118,116,114,114,116,107,92,85,97,101,103,106,99,95,93,96,105,111,66,67,69,68,69,72,76,72,50,71,72,73,72,66,72,75,78,72,74,69,68,64,69,73,65,68,65,59,63,62,66,69
105,103,103,101,107,114,113,108,100,118,117,117,118,116,114,113,107,112,117,117,123,85,105,111,111,112,115,114,117,115,110,115,101,101,102,104,104,108,109,104,96,110,109,111,110,108,110,110,104,106,111,110,116,82,96,99,105,108,110,106,106,106,105,106,65,69,67,63,68,70,73,68,58,72,71,73,71,70,68,70,64,68,73,69,75,60,68,72,67,66,64,67,69,65,65,71
106,104,103,101,103,108,110,119,109,108,121,121,117,121,123,119,125,120,111,107,129,104,114,107,108,113,113,113,115,112,119,119,101,99,98,97,100,102,103,110,104,99,114,113,111,113,114,109,117,113,107,106,123,98,105,97,101,110,108,108,108,108,109,109,67,65,64,63,64,64,69,69,64,64,73,74,73,75,73,70,79,72,69,70,95,72,77,72,60,70,68,68,60,66,70,70
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103,107,116,113,112,109,110,115,114,97,102,116,115,115,117,113,119,119,116,115,120,122,128,116,115,116,125,116,120,123,122,118,99,103,106,105,105,105,103,106,102,87,93,111,111,108,109,105,108,114,108,110,111,111,115,105,108,108,115,105,116,116,110,110,67,67,67,67,71,69,68,71,69,56,58,71,73,73,71,66,71,74,70,70,70,68,75,64,67,69,70,70,74,75,71,71]
<h1 style="color:# 麦片财富积分
关注者： 1
附件二中对应矩阵
附件二对应矩阵：
b=[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
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0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0.,0,0,0,0,0,0,0
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]
<h1 style="color:# 麦片财富积分
关注者： 1
回复 4# libralibra 的帖子
你好，我现在把那两个框起来了，但是是用的很笨的赋值循环之类的，没有通用性，想问下您有没有比较好的想法？可以使程序通用的？
关注者： 195
做个初等操作。希望有所帮助
I = imread('c:\\ce.png');
A = load('c:\\duiying.txt');
bw = im2bw(A, graythresh(A));
L = bwlabel(bw);
stats = regionprops(L);
Ar = cat(1, stats.Area);
[Ar1, ind] = sort(Ar, 'descend');
bd1 = stats(ind(1)).BoundingB
bd2 = stats(ind(2)).BoundingB
rectangle('position', bd1, 'edgecolor', 'r')
rectangle('position', bd2, 'edgecolor', 'r')
未命名.bmp (1.07 MB, 下载次数: 68)
09:46 上传
关注者： 57
untitled.jpg (1.34 KB, 下载次数: 14)
10:23 上传
untitled1.jpg (1.41 KB, 下载次数: 5)
10:23 上传
[x,y]=find(b~=0)
&& x1=min(x)
&& y1=min(y)
&& x2=max(x)
&& y2=max(y)
&& imshow(b),hold on,rectangle('Position',[y1,x1,y2-y1,x2-x1],'edgecolor', 'r')
[color=red][size=5][b]相互学习共同进步 若帮到你请给威望和评分[/b][/size] [/color]
<h1 style="color:# 麦片财富积分
关注者： 1
回复 8# lyqmath 的帖子
O(∩_∩)O谢谢，很不错~~去给你投票支持下你~~:victory:
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