The following ASCII table contains both ASCII control characters, ASCII printable characters and the extended ASCII character set ISO 8859-1, also called ISO Latin1
ASCII Code
ASCII Code - The extended ASCII table
ASCII stands for American Standard Code for Information Interchange. It's a 7-bit character code where every single bit represents a unique character. On this webpage you will find 8 bits, 256 characters, according to ISO 8859-1 and Microsoft(R) Windows Latin-1 increased characters, which is available in certain programs such as Microsoft Word.
ASCII control characters (character code 0-31)
The first 32 characters in the ASCII-table are unprintable control codes and are used to control peripherals such as printers.
000000NUL�&Null char
100101SOH&Start of Heading
200202STX&Start of Text
300303ETX&End of Text
400404EOT&End of Transmission
500505ENQ&Enquiry
600606ACK&Acknowledgment
700707BEL&Bell
801008 BS&Back Space
901109 HT	&Horizontal Tab
100120A LF
&Line Feed
110130B VT&Vertical Tab
120140C FF&Form Feed
130150D CR
&Carriage Return
140160E SO&Shift Out / X-On
150170F SI&Shift In / X-Off
1602010DLE&Data Line Escape
1702111DC1&Device Control 1 (oft. XON)
1802212DC2&Device Control 2
1902313DC3&Device Control 3 (oft. XOFF)
2002414DC4&Device Control 4
2102515NAK&Negative Acknowledgement
2202616SYN&Synchronous Idle
2302717ETB&End of Transmit Block
2403018CAN&Cancel
2503119 EM&End of Medium
260321ASUB&Substitute
270331BESC&Escape
280341C FS&File Separator
290351D GS&Group Separator
300361E RS&Record Separator
310371F US&Unit Separator
ASCII printable characters (character code 32-127)
Codes 32-127 are common for all the different variations of the ASCII table, they are called printable characters, represent letters, digits, punctuation marks, and a few miscellaneous symbols. You will find almost every character on your keyboard. Character 127 represents the command DEL.
3204020& &Space
3304121!!&Exclamation mark
3404222""&Double quotes (or speech marks)
3504323##&Number
3604424$$&Dollar
3704525%%&Procenttecken
3804626&&&Ampersand
3904727''&Single quote
4005028((&Open parenthesis (or open bracket)
4105129))&Close parenthesis (or close bracket)
420522A**&Asterisk
430532B++&Plus
440542C,,&Comma
450552D--&Hyphen
460562E..&Period, dot or full stop
470572F//&Slash or divide
480603000&Zero
490613111&One
500623222&Two
510633333&Three
520643444&Four
530653555&Five
540663666&Six
550673777&Seven
560703888&Eight
570713999&Nine
580723A::&Colon
590733B;;&Semicolon
600743C<<&Less than (or open angled bracket)
610753D==&Equals
620763E>>&Greater than (or close angled bracket)
630773F??&Question mark
6410040@@&At symbol
6510141AA&Uppercase A
6610242BB&Uppercase B
6710343CC&Uppercase C
6810444DD&Uppercase D
6910545EE&Uppercase E
7010646FF&Uppercase F
7110747GG&Uppercase G
7211048HH&Uppercase H
7311149II&Uppercase I
741124AJJ&Uppercase J
751134BKK&Uppercase K
761144CLL&Uppercase L
771154DMM&Uppercase M
781164ENN&Uppercase N
791174FOO&Uppercase O
8012050PP&Uppercase P
8112151QQ&Uppercase Q
8212252RR&Uppercase R
8312353SS&Uppercase S
8412454TT&Uppercase T
8512555UU&Uppercase U
8612656VV&Uppercase V
8712757WW&Uppercase W
8813058XX&Uppercase X
8913159YY&Uppercase Y
901325AZZ&Uppercase Z
911335B[[&Opening bracket
921345C\\&Backslash
931355D]]&Closing bracket
941365E^^&Caret - circumflex
951375F__&Underscore
9614060``&Grave accent
9714161aa&Lowercase a
9814262bb&Lowercase b
9914363cc&Lowercase c
10014464dd&Lowercase d
10114565ee&Lowercase e
10214666ff&Lowercase f
10314767gg&Lowercase g
10415068hh&Lowercase h
10515169ii&Lowercase i
1061526Ajj&Lowercase j
1071536Bkk&Lowercase k
1081546Cll&Lowercase l
1091556Dmm&Lowercase m
1101566Enn&Lowercase n
1111576Foo&Lowercase o
11216070pp&Lowercase p
11316171qq&Lowercase q
11416272rr&Lowercase r
11516373ss&Lowercase s
11616474tt&Lowercase t
11716575uu&Lowercase u
11816676vv&Lowercase v
11916777ww&Lowercase w
12017078xx&Lowercase x
12117179yy&Lowercase y
1221727Azz&Lowercase z
1231737B{{&Opening brace
1241747C||&Vertical bar
1251757D}}&Closing brace
1261767E~~&Equivalency sign - tilde
1271777F&Delete
The extended ASCII codes (character code 128-255)
There are several different variations of the 8-bit ASCII table. The table below is according to ISO 8859-1, also called ISO Latin-1. Codes 128-159 contain the Microsoft(R) Windows Latin-1 extended characters.
12820080€€&Euro sign
12920181&&&&
13020282‚‚&Single low-9 quotation mark
13120383ƒƒ&Latin small letter f with hook
13220484„„&Double low-9 quotation mark
13320585……&Horizontal ellipsis
13420686††&Dagger
13520787‡‡&DDouble dagger
13621088ˆˆ&Modifier letter circumflex accent
13721189‰‰&Per mille sign
1382128AŠŠ&SLatin capital letter S with caron
1392138B‹‹&Single left-pointing angle quotation
1402148CŒŒ&OELatin capital ligature OE
1412158D&&&&
1422168EŽŽ&Latin captial letter Z with caron
1432178F&&&&
14422090&&&&
14522191‘‘&Left single quotation mark
14622292’’&Right single quotation mark
14722393““&Left double quotation mark
14822494””&Right double quotation mark
14922595••&Bullet
15022696––&En dash
15122797——&Em dash
15223098˜˜&Small tilde
15323199™™&Trade mark sign
1542329Ašš&Latin small letter S with caron
1552339B››& Single right-pointing angle quotation mark
1562349Cœœ&Latin small ligature oe
1572359D&&&&
1582369Ežž&Latin small letter z with caron
1592379FŸŸ&YLatin capital letter Y with diaeresis
160240A0& &Non-breaking space
161241A1?¡&Inverted exclamation mark
162242A2?¢&Cent sign
163243A3?£&Pound sign
164244A4¤¤&Currency sign
165245A5?¥&Yen sign
166246A6?¦&Pipe, Broken vertical bar
167247A7§§&Section sign
168250A8¨¨&Spacing diaeresis - umlaut
169251A9(C)©&Copyright sign
170252AA?ª&Feminine ordinal indicator
171253AB<<«&Left double angle quotes
172254AC?¬&Not sign
173255AD-­&Soft hyphen
174256AE(R)®&Registered trade mark sign
175257AF?¯&Spacing macron - overline
176260B0°°&Degree sign
177261B1±±&Plus-or-minus sign
178262B2?²²Superscript two - squared
179263B3?³³Superscript three - cubed
180264B4?´&Acute accent - spacing acute
181265B5uµ&Micro sign
182266B6?¶&Pilcrow sign - paragraph sign
183267B7··&Middle dot - Georgian comma
184270B8,¸&Spacing cedilla
185271B9?¹¹Superscript one
186272BA?º&Masculine ordinal indicator
187273BB>>»&Right double angle quotes
188274BC 1/4 ¼¼Fraction one quarter
189275BD 1/2 ½½Fraction one half
190276BE 3/4 ¾¾Fraction three quarters
191277BF?¿&Inverted question mark
192300C0?À&ALatin capital letter A with grave
193301C1?Á&ALatin capital letter A with acute
194302C2?Â&ALatin capital letter A with circumflex
195303C3?Ã&ALatin capital letter A with tilde
196304C4?Ä&ALatin capital letter A with diaeresis
197305C5?Å&ALatin capital letter A with ring above
198306C6AEÆ&AELatin capital letter AE
199307C7?Ç&CLatin capital letter C with cedilla
200310C8?È&ELatin capital letter E with grave
201311C9?É&ELatin capital letter E with acute
202312CA?Ê&ELatin capital letter E with circumflex
203313CB?Ë&ELatin capital letter E with diaeresis
204314CC?Ì&ILatin capital letter I with grave
205315CD?Í&ILatin capital letter I with acute
206316CE?Î&ILatin capital letter I with circumflex
207317CF?Ï&ILatin capital letter I with diaeresis
208320D0?ÐÐLatin capital letter ETH
209321D1?Ñ&NLatin capital letter N with tilde
210322D2?Ò&OLatin capital letter O with grave
211323D3?Ó&OLatin capital letter O with acute
212324D4?Ô&OLatin capital letter O with circumflex
213325D5?Õ&OLatin capital letter O with tilde
214326D6?Ö&OLatin capital letter O with diaeresis
215327D7××&Multiplication sign
216330D8?Ø&OLatin capital letter O with slash
217331D9?Ù&ULatin capital letter U with grave
218332DA?Ú&ULatin capital letter U with acute
219333DB?Û&ULatin capital letter U with circumflex
220334DC?Ü&ULatin capital letter U with diaeresis
221335DD?Ý&YLatin capital letter Y with acute
222336DE?ÞÞLatin capital letter THORN
223337DFssß&Latin small letter sharp s - ess-zed
224340E0àà&Latin small letter a with grave
225341E1áá&Latin small letter a with acute
226342E2?â&Latin small letter a with circumflex
227343E3?ã&Latin small letter a with tilde
228344E4?ä&Latin small letter a with diaeresis
229345E5?å&Latin small letter a with ring above
230346E6aeæ&Latin small letter ae
231347E7?ç&Latin small letter c with cedilla
232350E8èè&Latin small letter e with grave
233351E9éé&Latin small letter e with acute
234352EAêê&Latin small letter e with circumflex
235353EB?ë&Latin small letter e with diaeresis
236354ECìì&Latin small letter i with grave
237355EDíí&Latin small letter i with acute
238356EE?î&Latin small letter i with circumflex
239357EF?ï&Latin small letter i with diaeresis
240360F0?ð&Latin small letter eth
241361F1?ñ&Latin small letter n with tilde
242362F2òò&Latin small letter o with grave
243363F3óó&Latin small letter o with acute
244364F4?ô&Latin small letter o with circumflex
245365F5?õ&Latin small letter o with tilde
246366F6?ö&Latin small letter o with diaeresis
247367F7÷÷&Division sign
248370F8?ø&Latin small letter o with slash
249371F9ùù&Latin small letter u with grave
250372FAúú&Latin small letter u with acute
251373FB?û&Latin small letter u with circumflex
252374FCüü&Latin small letter u with diaeresis
253375FD?ý&Latin small letter y with acute
254376FE?þ&Latin small letter thorn
255377FF?ÿ&Latin small letter y with diaeresis当前位置： >
& 已知函数f x xlnx g x 已知函数f(x)=a/x+xlnx,g(x)=x3-x2-3
已知函数f x xlnx g x 已知函数f(x)=a/x+xlnx,g(x)=x3-x2-3
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已知函数f(x)=a/x+xlnx,g(x)=x3-x2-3 通过求导可知,g(x)在[1/2,2]先减后增,最大值1 研究f(x) f(x)=-a/x^2 + lnx +1 , [1/2,2] 1、 a &0 所以f(x) & 0 f(1/2)》1 无解 2、a&0 f(x)是增函数, (1)、f(x)》0 这时,f(1/2)》0 , 0&a《0.25(1-ln0.5) 又 f(1/2)》1,a》0.5-0.25ln0.5 综上无解 (2)、f(x)《0 这时,f(2)《0 , a》4+4ln2 又 f(2)》1, 综上 a》4+4ln2 (3)、f(x) 先小于零后大于零 0.25(1-ln0.5)&a&4+4ln2 f(x)先减后增 f(1/2)》1 且 f(2)》1 综上 0.5-0.25ln0.5《a&4+4ln2 所以 a》0.5-0.25ln0.5。已知函数f(x)=xlnx,g(x)=x^3 ax^2-x 2,若不等式2f(x)小于等于g(t。f(x)=xlnxg(x)=x^3+2ax^2+2x&0,2f(x)&=g(x)+2x&0,g(x)+2-2f(x)&=0F(x)=g(x)+2-2f(x)=x^3+2ax^2+4-2xlnx F(x)=3x^2+4ax-2lnx-2F(x)=6x+4a-2/x,x=根号(a^2-3)-ax&02f(x)≤g(x)+2a≤-1.3256
2f(x)≤g(x)+2 ==&g(x)+2-2f(x)≥0 ==&3x^2+2ax-1+2-2xlnx≥0 ==&3x+2a+1/x-2lnx≥0 ==&3x+1/x-2lnx≥-2a ==&lnx-3x/2-1/2x≤a 令h(x)。已知函数f(x)xlnx,g(x)=x^3+ax^2-x+2.(1)如果函数g(x)的单调递。答:f(x)=xlnx,g(x)=x^3+ax^2-x+21)求导得:g(x)=3x^2+2ax-1g(x)单调减区间为(-1/3,1)表明x=-1/3和x=1是g(x)=0的解x=1代入得:3+2a-1=0解得:a=-1所以:g(x)=x^3-x^2-x+2,g(x)=3x^2-2x-1点P(-1,1)处:g(-1)=-1-1+1+2=1,g(x)=3+2-1=4点P在g(x)上,所以切线方程为:y-1=4(x+1),y=4x+52)2f(x)&=g(x)+2=3x^2+2ax-1+2=3x^2+2ax+1在区间[1,2]上有解2xlnx&=3x^2+2ax+12xlnx-3x^2-1&=2ax在区间[1,2]上有解所以:2a&=2lnx-3x-1/x在[1,2]上有解设h(x)=2lnx-3x-1/x求导:h(x)=2/x-3+1/x^2=-(3x^2-2x-1)/x^2=-(3x+1)(x-1)/x^2&0所以:h(x)在区间[1,2]上是减函数h(2)&=h(x)&=h(1)2ln2-6-1/2&=h(x)&=0-3-12ln2-13/2&=h(x)&=-4所以:2a&=2ln2-13/2所以:a&=ln2-。已知函数f(x)=xlnx 若函数G(x)=f(x)+x^2+ax+2有零点,求实数a。已知函数f(x)=xlnx 1、若函数G(x)=f(x)+x^2+ax+2有零点,求实数a的最大值 2、若任取x大于0,f(x)/x小于等于x-kx^2-1恒成立,求实数k的取值范围(1)解析:∵函数f(x)=xlnx 令f’(x)=lnx+1=0==&x=1/e,f’’(x)=1/x&0 ∴函数f(x)在x=1/e处取极小值-1/e ∵函数G(x)=f(x)+x^2+ax+2有零点 G(x)=xlnx+x^2+ax+2==&G’(x)=lnx+1+2x+a=0 G’’(x)=1/x+2&0,∴G(x)在定义域内存在极小值 ∴当x=1,a=-3时,G’(x)=0,即当a=-3时,G(x)在x=1处取极小值0 ∴当a&=-3时,G(x)有零点 令a=h(x)=(xlnx+x^2+2)/(-x)==&h’(x)=-[x+x^2-2]/(-x)^2=0 x+x^2-2=0==&x=1 当0&x&1时,h’(x)&0;当x&1时,h’(x)&0; ∴h(x)在x=1处取极大值h(1)=-3 ∴实数a。已知函数f(x)=xlnx,g(x)=x–1求函数fx–gx的极小值令h(x)=f(x)-g(x)=xlnx-x+1h(x)=lnx +1-1=lnx=0x=1x&1,h(x)&0x&1,h(x)&0所以x=1处极小值=0
我输学不学 我数学不好。已知函数f(x)=xlnx,g(x)=k(x-1) (I)若f(x)≥g(x)恒成立,求实数k的。=1,做函数F(x)=xlnx-k(x-1),对其求道可得F‘(x)=lnx+1-k,可以知道F(x)在e^(k-1)为最小值,又因为x=1时候F(x)=0,所以只能e^(k-1)=1。已知函数f(x)=xlnx,g(x)=-x^2+ax-3 那给我吧^^。在线等!已知函数f(x)=xlnx,g(x)=x/e^x-2/ef(x)=xlnxf(x)=xlnx的导数为lnx+1 在区间[1,3]恒大于0所以f(x)=xlnx 在区间[1,3]单调递增最小值为f(1)=1 (2)f(x)=1+lnx 故f在(负无穷,1/e)递减,在(1/e,正无穷)递增。即f(1/e)=-1/e是f的最小值。另一方面,g(x)=e^(-x)*(1-x),故同理g(1)=-1/e是g的最大值。即 f(m)&=-1/e, g(n)&=-1/e 故有f(m)&=g(n)
f(x)=1+lnx 故f(x)在(负无穷,1/e)递减,在(1/e,正无穷)递增。即在[1,3]递增即f(1)=0是f(x)的最小值。g(x)=e^(-x)*(1-x),故同理g(1)=-。
(1)f(x)=1+lnx.令f(x)=0得x=1/e, 故f在(0,1/e)递减,在(1/e,+∞)递增。所以f(x)在区间[1,3]单调递增最小值为f(1)=1.(2)由(。
(1)对f(x)求导,为(lnx+1),在[1,3]内恒大于0,即单增,可知,f(x)在x=1处取得最小值,为0;(2)你那个条件怎么回事啊,请再确定一下!已知函数f(x)=xlnx,g(x)=x^3+ax^2-x+2,若 2f(x)≤g`(x)+2在x_百。g(x)=3x2+2ax-1不等式2f(x)≤g(x)+2根据 ln x ,可知 x≥0∴x&0时,2xlnx≤3x2+2ax+1恒成立即2a≥2lnx-3x-1/x恒成立设h(x)=2lnx-3x-1/x(x&0), h(x)=2/x-3+1/x2 =(-3x2+2x+1)/x2
=-(3x+1)(x-1)/x2∴x∈(0,1)时,h(x)&0,h(x)递增 x∈(1,+∞)时,h(x)&0,h(x)递减∴当x=1时,h(x)max=h(1)=0∴2a≥h(x)max=0a≥0。已知函数f[x]=xlnx,设g[x]=f[x]=ln[1+x]_x,判断g[x]的导数零点。你的表达不是很清楚,我按我的理解帮你做一下!f(x)=xlnxg(x)=f(x)+ln(1+x)-x=xlnx+ln(1+x)-xg(x)=lnx+1+1/(x+1)-1=lnx +1/(x+1)g(x)的零点,即方程lnx +1/(x+1)=0的根方程化成lnx=-1/(x+1)构造两个函数y=lnx y=-1/(x+1)在同一坐标系内作出这两个函数的图象观察它们的交点仅有一个,故方程一解也就是导数的零点为一个。
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用定义证明lim(x-&1)(x^2+2x-1)=2
deffier123 用定义证明lim(x-&1)(x^2+2x-1)=2
e|x-1|<，得lim(x-&1)(x^2+2x-1)=2x-&|x-1|&10<：|x^2+2x-1-2|&x&1;e/5|x-1|<,所以不妨设 |x-1|&5取 δ=min{1;2任给e>,e/δ时恒有;5}当 0&0|x^2+2x-1-2|=|(x-1)(x+3)|&e所以由定义
任意e>，使对所有x，满足|x-1|<，存在正数D=√(e+4)-2，都有|x^2+2x-1-2|=|x^2+2x-3|=|(x+3)(x-1)|=|x+3||x-1|&(D+4)D=e所以lim(x-&0;D
lim(x-&1)(x^2+2x-1)=lim(x-&1)（X+1）^2-2（X+1）^2为增函数，所以当x-&1时 带入得（X+1）^2-2=2所以lim(x-&1)(x^2+2x-1)=2已知函数f（x）=log2（1/x+1），x》0 且（1/2）^x-1, x&0. 若f（3-2a^2)&f(a),则a的取值范围是多少？, 已知函数f（x）=log2（1/x+
已知函数f（x）=log2（1/x+1），x》0 且（1/2）^x-1, x&0. 若f（3-2a^2)&f(a),则a的取值范围是多少？ 要详细解答，给高分 chengyiling011 已知函数f（x）=log2（1/x+1），x》0 且（1/2）^x-1, x&0. 若f（3-2a^2)&f(a),则a的取值范围是多少？
x=0时最大值f(0)= log2【1/2)^x单调减，x≥0f(x) = (1/(x+1)单调减，即（2a+3)(a-1)＞0∴a<，∴f(x) = (1/2 ;-3/，∵f（3-2a^2)&2)^x -1单调减，∵(1/(0+1)】=0当x<，∵x+1单调增;f(a)∴3-2a^2＜a∴2a^2+a-3&2)^x - 1，x趋近于0时f(x)min趋近于(1/0;(x+1))单调减，x＜0当x≥0时;0时，∴1/2)^0-1=0∴f(x)在R上单调减对于减函数，∴f(x)=log2(1/，或a>f(x) = log2【1/(x+1)】
f(0)=0因此在R上为单调减函数由f（3-2a^2)&f(a)得;2，且在x=0时连续;-3/, 及x&1 or a&0解得：a&a(2a+3)(a-1)>：3-2a^2&0都是单调减函数;=0f(x)在x>
