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01:38 提供
设p=3+2*3+2*（3^2）+2*（3^3）+2*（3^4）+2*（3^5）+......+2*（3^2017）问:数p=？
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n/2-(5-n)/3=0→n=2则p=C(2,5)·（-1）^(5-2)=-10则当0&x≤1时 f(x)=3x²+1积分得π/4 + (1+1)=π/4 + 2
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猜你感兴趣Scan report for http://cdn.adnxs.com/p/3a/e6/8f/c4/3ae68fcf503bb57ed923e7.swf?clickTAG=http://ams1.ib.adnxs.com/click?ot9sHfrN1j_Xo3A9CtfTP0SLbOf7qQZAWpucVbcV8D9iIkfPAX3yP5xAJVPflEs5boY-hhGlMiDnZbpTAAAAAGtTLQBlAQAAGgcAAAIAAACWRrwAPWQAAAAAAQBVU0QAVVNEACwB-gD8AdsEUGgBAgUAAQMAAAAA6CUjlAAAAAA./cnd=!8gVcNwiZsbcBEJaN8QUYvcgBIAA./referrer=http://www.mediafire.com/download/xp9af72io8ckwc2/Launcher+Zona+Minecraft+2+-+v5.0.exe/clickenc=http://us-ads.openx.net/w/1.0/rc?ts=1fHJpZD01ZjNlZjEwMS05YTgxLTQzOTItYTIwMy1hYmY1YjE4Y2Q4YjF8cnQ9MTQwNDcyNDcxMXxhdWlkPTI0NTcwM3xhdW09RE1JRC5XRUJ8c2lkPTQ4ODc3fHB1Yj02MjM3MnxwYz1VU0R8cmFpZD1hZTZhNzY1Yy0zMzBiLTRjZjUtOWYwNC1mMWVlYTVjODBhMTh8YWlkPTUzNzE1NzY5N3x0PTEyfGFzPTMwMHgyNTB8bGlkPTUzNzEyNTMxNHxvaWQ9NTM3MTAxOTcxfHA9MzEwfHByPTI1MHxhZHY9NTM3MDcyNDAwfGFjPVVTRHxwbT1QUklDSU5HLkNQTXxtPTF8YWk9MTUyZDA3YjEtZGE0MS00YzQwLWFkMTgtZmU3NGMyNjk1MzRhfG0zPTF8bWM9VVNEfG1yPTYwfHBpPTI1MHxtdWk9NThlYzBlNmUtZGQ1Zi00MDQwLWFlZDgtYmM2ZjhlNWM1MDkyfG1hPTI2ZWI5OWJiLWIwODQtNDA0OC1hYzRjLThhZWNlMzljZDc0MnxtcnQ9MTQwNDcyNDcxMXxtcmM9U1JUX1dPTnxtd2E9NTM3MDcyNDAwfGNrPTF8bXdiaT0yNjI3fG13Yj0xMDAwfG1hcD0zMTB8ZWxnPTF8bW9jPVVTRHxtb3I9NjB8bXBjPVVTRHxtcHI9MjUwfG1wZj0yNTB8bW1mPTI1MHxtcG5mPTI1MHxtbW5mPTI1MHxwY3Y9OXxtbz1PWHxlYz0xMjMzODgzOHxtd2M9NTM3MTAxOTcxfG13cD01MzcxMjUzMTR8bXdjcj01MzcxNTc2OTd8bXdpcz0xfG13aW89MXxtd3B0PW94X3Byb3RvfHVyPWlMa2xudzJHYmM&r=http://mt.k.keyade.com/mck/1/?kaPt=appnexus&kaPcId=68454&kaTckM=p&kaAcId=390&kaCpnId=&kaCpnPtId=899330&kaAdgPtId=3004569&kaTckId=&kaRef=http%3A%2F%2Fwww.mediafire.com%2Fdownload%2Fxp9af72io8ckwc2%2FLauncher%20Zona%20Minecraft%202%20-%20v5.0.exe at
22:13:36 UTC - VirusTotal
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Webutation
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SCUMWARE.org
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SecureBrain
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Yandex Safebrowsing
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StopBadware
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advertisements
Final URL after redirects
http://cdn.adnxs.com/p/3a/e6/8f/c4/3ae68fcf503bb57ed923e7.swf?clickTAG=http://ams1.ib.adnxs.com/click?ot9sHfrN1j_Xo3A9CtfTP0SLbOf7qQZAWpucVbcV8D9iIkfPAX3yP5xAJVPflEs5boY-hhGlMiDnZbpTAAAAAGtTLQBlAQAAGgcAAAIAAACWRrwAPWQAAAAAAQBVU0QAVVNEACwB-gD8AdsEUGgBAgUAAQMAAAAA6CUjlAAAAAA./cnd=!8gVcNwiZsbcBEJaN8QUYvcgBIAA./referrer=http://www.mediafire.com/download/xp9af72io8ckwc2/Launcher+Zona+Minecraft+2+-+v5.0.exe/clickenc=http://us-ads.openx.net/w/1.0/rc?ts=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&r=http://mt.k.keyade.com/mck/1/?kaPt=appnexus&kaPcId=68454&kaTckM=p&kaAcId=390&kaCpnId=&kaCpnPtId=899330&kaAdgPtId=3004569&kaTckId=&kaRef=http%3A%2F%2Fwww.mediafire.com%2Fdownload%2Fxp9af72io8ckwc2%2FLauncher%20Zona%20Minecraft%202%20-%20v5.0.exe
IP address resolution
64.145.86.43
HTTP Response code
HTTP Response headers
content-length: 33543
via: HTTP/1.1 GWA
accept-ranges: bytes
x-google-cache-control: remote-fetch
server: Apache
last-modified: Thu, 05 Jun :07 GMT
connection: keep-alive
etag: &3ae68fcf503bb57ed923e7:&
date: Mon, 07 Jul :46 GMT
content-type: application/x-shockwave-flash
Response content SHA256
c7bc69aebb9f90c96c315fe9fcccaa930f19c63b854db626a77d49a7
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Username or email以下试题来自：
问答题设随机变量X的分布律为PX=k)=p(1-p)k-1(k=1，2，…)，Y在1～k之间等可能取值，求PY=3)． [*]
由全概率公式得
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1.问答题 [*]2.问答题 [*]3.问答题 [*]则φ(x)在[0，2]上连续，在(0，2)内可导，且φ(0)=φ(1)=φ(2)=0，
因此φ(x)在[0，1]和[1，2]上都满足罗尔定理的...... 4.填空题 -4，-2，25.填空题 [*]
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设 p,q 为质数,且 p^3+q^3+1=p^2q^2,求 (p,q)
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首先若p = q, 有2p&#179; = p^4-1 = (p-1)(p+1)(p&#178;+1), 右端各项均不被p整除, 矛盾.不妨设p < q.若p = 2, q&#179;+9 = 4q&#178;, (q-3)(q&#178;-q-3) = 0, 有一个整数解q = 3.若p > 2, 则由q > p有q > p+1.将原式移项得p&#179;+1 = p&#178;q&#178;-q&#179; = q&#178;(p&#178;-q), 有q&#178; | p&#179;+1 = (p+1)(p&#178;-p+1).而q > p+1, 因此q&#178;与p+1互素, 于是q&#178; | p&#178;-p+1.但0 < p&#178;-p+1 < (p+1)&#178; < q&#178;, q&#178;不可能整除p&#178;-p+1, 矛盾.综上, 只有(2,3)与(3,2)两组满足条件.
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