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to find out more about this error.& 解下列方程．（第一题写出验算过程）x÷4.5=2.10.2x
本题难度：0.50&&题型：解答题
解下列方程．（第一题写出验算过程）x÷4.5=2.1&&&&&&&&&&&&&&&&&&&&&0.2x+3×0.9=5.43（x+2.7）=3.5&&&&&&&&&&&&&&&&&&&&&x-0.36x=16．
来源：学年新人教版五年级（上）期末数学试卷（27） | 【考点】方程的解和解方程．
解下列方程．x+4.8=7.2&&&&&&&&&&x-6.5=3.2&&&&&&&&&&&&&x÷8=0.46x+18=48&&&&&&&&&3（x+2.1）=10.5&&&&&&&&12x-9x=8.720-x=9&&&&&&&&&&&6.3÷x=7&&&&&&&&&&&（x-3）÷2=7.5
解下列方程．①x+4.8=7.2&&&&&&&&&&&②x-6.5=3.2&&&&&&&&&&&&③x÷8=0.4④3（x+2.1）=10.5&&&&&&&&&⑤8x-4×14=0&&&&&&&⑥7x÷3=8.19．
解下列方程．x×4=÷x=（-）x=x+=1．
解析与答案
（揭秘难题真相，上）
习题“解下列方程．（第一题写出验算过程）x÷4.5=2.10.2x+3×0.9=5.43（x+2.7）=3.5x-0.36x=16．”的学库宝（http://www.xuekubao.com/）教师分析与解答如下所示：
【分析】（1）根据等式的性质在方程两边同时乘45得解验算时把方程的解代入原方程如果方程的左边等于右边就说明是原方程的解否则就不是原方程得解（2）先计算3×09=27再根据等式的性质在方程两边同时减去27再同时除以02得解（3）根据等式的性质在方程两边同时除以3再同时减去27得解（4）先计算x-036x=064x再根据等式的性质在方程两边同时乘064得解．
【解答】解：（1）x÷45=21&nbsp&nbsp&nbsp x÷45×45=21×45&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp x=945把x=945代入原方程左边=945÷45=21右边=21左边=右边所以x=945是原方程的解（2）02x+3×09=54&nbsp&nbsp 02x+27-27=54-27&nbsp&nbsp&nbsp&nbsp&nbsp 02x÷02=27÷02&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp x=135（3）3（x+27）=35&nbsp&nbsp3（x+27）÷3=35÷3&nbsp&nbsp&nbsp&nbsp&nbsp x+27-27=76-27&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp x=-2315（4）x-036x=16&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp 064x=16&nbsp064x÷064=16÷064&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbspx=25．
【考点】方程的解和解方程．
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知识点讲解
经过分析，习题“解下列方程．（第一题写出验算过程）x÷4.5=2.10.2x”主要考察你对
等考点的理解。
因为篇幅有限，只列出部分考点，详细请访问。
方程的解与解方程
1.方程的解的定义：方程两边左右相等的未知数的值叫做方程的解。 2.解方程：求方程的解的过程叫做解方程。
名师视频同步辅导
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I was trying to build an opengl program on qt creator, installed on my mac, with osx 10.9.
I got several warnings on glut functions about its deprecation in osx10.9, a sample error message is like:
'glutInit' is deprecated: first deprecated in OS X 10.9 [-Wdeprecated-declarations]
glutInit(&argc, &argv);
I wonder if GLUT.h is not usable anymore in osx10.9? According to some other posts, it is said that as long as we change "OS X Deployment Target" back to OSX10.8, then it works. How to do so in qtcreator? Thank you!
You can still use it in 10.9. They're sending you a pretty strong signal that they want you to stop, though...
You can disable those warnings with the -Wno-deprecated-declarations compiler option.
There's also some difficulties including the right headers if you're trying to use GL3 level features, because you need to include gl3.h for that, while glut.h includes gl.h, which causes additional complaints about possible conflicts while building. The somewhat hacky workaround I found for this is to prevent glut.h from including gl.h by defining the header guard:
#include &OpenGL/gl3.h&
#define __gl_h_
#include &GLUT/glut.h&
Then, for using GL3+ level features, you need to specify that with an additional flag to glutInitDisplayMode():
glutInitDisplayMode(... | GLUT_3_2_CORE_PROFILE);
It looks like it's probably time to start using GLFW. I never used GLUT for anything serious, but it was always very convenient for small demos/tests.
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