.查询大学英语的总成绩和平均成绩。update select from, from course,score w

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所需积分:02、查询&生物&课程比&物理&课程成绩高的所有学生的学号;
获取所有有生物课程的人(学号,成绩) - 临时表
获取所有有物理课程的人(学号,成绩) - 临时表
根据【学号】连接两个临时表:
然后再进行筛选
select A.student_id,sw,ty from
(select student_id,num as sw from score left join course on score.course_id = course.cid where ame = '生物') as A
(select student_id,num
as ty from score left join course on score.course_id = course.cid where ame = '体育') as B
on A.student_id = B.student_id where sw & if(isnull(ty),0,ty);
3、查询平均成绩大于60分的同学的学号和平均成绩;
根据学生分组,使用avg获取平均值,通过having对avg进行筛选
select student_id,avg(num) from score group by student_id having avg(num) & 60
4、查询所有同学的学号、姓名、选课数、总成绩;
select score.student_id,sum(score.num),count(score.student_id),student.sname
score left join student on score.student_id = student.sid
group by score.student_id
5、查询姓&李&的老师的个数;
select count(tid) from teacher where tname like '李%'
select count(1) from (select tid from teacher where tname like '李%') as B
6、查询没学过&叶平&老师课的同学的学号、姓名;
先查到&李平老师&老师教的所有课ID
获取选过课的所有学生ID
学生表中筛选
select * from student where sid not in (
select DISTINCT student_id from score where score.course_id in (
select cid from course left join teacher on course.teacher_id = teacher.tid where tname = '李平老师'
7、查询学过&001&并且也学过编号&002&课程的同学的学号、姓名;
先查到既选择001又选择002课程的所有同学
根据学生进行分组,如果学生数量等于2表示,两门均已选择
select student_id,sname from
(select student_id,course_id from score where course_id = 1 or course_id = 2) as B
left join student on B.student_id = student.sid group by student_id HAVING count(student_id) & 1
8、查询学过&叶平&老师所教的所有课的同学的学号、姓名;
同上,只不过将001和002变成 in (叶平老师的所有课)
9、查询课程编号&002&的成绩比课程编号&001&课程低的所有同学的学号、姓名;
10、查询有课程成绩小于60分的同学的学号、姓名;
select sid,sname from student where sid in (
select distinct student_id from score where num & 60
11、查询没有学全所有课的同学的学号、姓名;
在分数表中根据学生进行分组,获取每一个学生选课数量
如果数量 == 总课程数量,表示已经选择了所有课程
select student_id,sname
from score left join student on score.student_id = student.sid
group by student_id HAVING count(course_id) = (select count(1) from course)
12、查询至少有一门课与学号为&001&的同学所学相同的同学的学号和姓名;
获取 001 同学选择的所有课程
获取课程在其中的所有人以及所有课程
根据学生筛选,获取所有学生信息
再与学生表连接,获取姓名
select student_id,sname, count(course_id)
from score left join student on score.student_id = student.sid
where student_id != 1 and course_id in (select course_id from score where student_id = 1) group by student_id
13、查询至少学过学号为&001&同学所有课的其他同学学号和姓名;
先找到和001的学过的所有人
然后个数 = 001所有学科
==》 其他人可能选择的更多
select student_id,sname, count(course_id)
from score left join student on score.student_id = student.sid
where student_id != 1 and course_id in (select course_id from score where student_id = 1) group by student_id having count(course_id) = (select count(course_id) from score where student_id = 1)
14、查询和&002&号的同学学习的课程完全相同的其他同学学号和姓名;
002学过的也学过
select student_id,sname from score left join student on score.student_id = student.sid where student_id in (
select student_id from score
where student_id != 1 group by student_id HAVING count(course_id) = (select count(1) from score where student_id = 1)
) and course_id in (select course_id from score where student_id = 1) group by student_id HAVING count(course_id) = (select count(1) from score where student_id = 1)
15、删除学习&叶平&老师课的score表记录;
delete from score where course_id in (
select cid from course left join teacher on course.teacher_id = teacher.tid where teacher.name = '叶平'
16、向SC表中插入一些记录,这些记录要求符合以下条件:①没有上过编号&002&课程的同学学号;②插入&002&号课程的平均成绩;
由于insert 支持
inset into tb1(xx,xx) select x1,x2 from tb2;
所有,获取所有没上过002课的所有人,获取002的平均成绩
insert into score(student_id, course_id, num) select sid,2,(select avg(num) from score where course_id = 2)
from student where sid not in (
select student_id from score where course_id = 2
17、按平均成绩从低到高 显示所有学生的&语文&、&数学&、&英语&三门的课程成绩,按如下形式显示: 学生ID,语文,数学,英语,有效课程数,有效平均分;
select sc.student_id,
(select num from score left join course on score.course_id = course.cid where ame = "生物" and score.student_id=sc.student_id) as sy,
(select num from score left join course on score.course_id = course.cid where ame = "物理" and score.student_id=sc.student_id) as wl,
(select num from score left join course on score.course_id = course.cid where ame = "体育" and score.student_id=sc.student_id) as ty,
count(sc.course_id),
avg(sc.num)
from score as sc
group by student_id desc
18、查询各科成绩最高和最低的分:以如下形式显示:课程ID,最高分,最低分;
select course_id, max(num) as max_num, min(num) as min_num from score group by course_
19、按各科平均成绩从低到高和及格率的百分数从高到低顺序;
思路:case when .. then
select course_id, avg(num) as avgnum,sum(case when score.num & 60 then 1 else 0 END)/count(1)*100 as percent from score group by course_id order by avgnum asc,
20、课程平均分从高到低显示(现实任课老师);
select avg(if(isnull(score.num),0,score.num)),teacher.tname from course
left join score on course.cid = score.course_id
left join teacher on course.teacher_id = teacher.tid
group by score.course_id
21、查询各科成绩前三名的记录:(不考虑成绩并列情况)
select score.sid,score.course_id,score.num,T.first_num,T.second_num from score left join
(select num from score as s2 where s2.course_id = s1.course_id order by num desc limit 0,1) as first_num,
(select num from score as s2 where s2.course_id = s1.course_id order by num desc limit 3,1) as second_num
score as s1
on score.sid =T.sid
where score.num &= T.first_num and score.num &= T.second_num
22、查询每门课程被选修的学生数;
select course_id, count(1) from score group by course_
23、查询出只选修了一门课程的全部学生的学号和姓名;
select student.sid, student.sname, count(1) from score
left join student on score.student_id
= student.sid
group by course_id having count(1) = 1
24、查询男生、女生的人数;
select * from
(select count(1) as man from student where gender='男') as A ,
(select count(1) as feman from student where gender='女') as B
25、查询姓&张&的学生名单;
select sname from student where sname like '张%';
26、查询同名同姓学生名单,并统计同名人数;
select sname,count(1) as count from st
27、查询每门课程的平均成绩,结果按平均成绩升序排列,平均成绩相同时,按课程号降序排列;
select course_id,avg(if(isnull(num), 0 ,num)) as avg from score group by course_id order by avg
asc,course_
28、查询平均成绩大于85的所有学生的学号、姓名和平均成绩;
select student_id,sname, avg(if(isnull(num), 0 ,num)) from score left join student on score.student_id = student.sid group by student_
29、查询课程名称为&数学&,且分数低于60的学生姓名和分数;
select student.sname,score.num from score
left join course on score.course_id = course.cid
left join student on score.student_id = student.sid
where score.num & 60 ame = '生物'
30、查询课程编号为003且课程成绩在80分以上的学生的学号和姓名;
select * from score where score.student_id = 3 and score.num & 80
31、求选了课程的学生人数
select count(distinct student_id) from score
select count(c) from (
select count(student_id) as c from score group by student_id) as A
32、查询选修&杨艳&老师所授课程的学生中,成绩最高的学生姓名及其成绩;
select sname,num from score
left join student on score.student_id = student.sid
where score.course_id in (select course.cid from course left join teacher on course.teacher_id = teacher.tid where tname='张磊老师') order by num desc limit 1;
33、查询各个课程及相应的选修人数;
select ame,count(1) from score
left join course on score.course_id = course.cid
group by course_
34、查询不同课程但成绩相同的学生的学号、课程号、学生成绩;
select DISTINCT s1.course_id,s2.course_id,s1.num,s2.num from score as s1, score as s2 where s1.num = s2.num and s1.course_id != s2.course_
35、查询每门课程成绩最好的前两名;
select score.sid,score.course_id,score.num,T.first_num,T.second_num from score left join
(select num from score as s2 where s2.course_id = s1.course_id order by num desc limit 0,1) as first_num,
(select num from score as s2 where s2.course_id = s1.course_id order by num desc limit 1,1) as second_num
score as s1
on score.sid =T.sid
where score.num &= T.first_num and score.num &= T.second_num
36、检索至少选修两门课程的学生学号;
select student_id from score group by student_id having count(student_id) & 1
37、查询全部学生都选修的课程的课程号和课程名;
select course_id,count(1) from score group by course_id having count(1) = (select count(1) from student);
38、查询没学过&叶平&老师讲授的任一门课程的学生姓名;
select student_id,student.sname from score
left join student on score.student_id = student.sid
where score.course_id not in (
select cid from course left join teacher on course.teacher_id = teacher.tid where tname = '张磊老师'
group by student_id
39、查询两门以上不及格课程的同学的学号及其平均成绩;
select student_id,count(1) from score where num & 60 group by student_id having count(1) & 2
40、检索&004&课程分数小于60,按分数降序排列的同学学号;
select student_id from score where num& 60 and course_id = 4
41、删除&002&同学的&001&课程的成绩;
delete from score where course_id = 1 and student_id = 2
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Student(S#,Sname,Sage,Ssex) 学生表 Course(C#,Cname,T#) 课程表 SC(S#,C#,score) 成绩表 Teacher(T#,Tname) 教师表问题: 1、查询“10”课程比“11”课程成绩高的所有学生的学号; select a.S# from (select s#,score from SC where C#='10') a,(select s#,score from SC where C#='11') b where a.score&b.score and a.s#=b.s#; 2、查询平均成绩大于 60 分的同学的学号和平均成绩; select S#,avg(score) from sc group by S# having avg(score) &60; 3、查询所有同学的学号、姓名、选课数、总成绩; select Student.S#,Student.Sname,count(SC.C#),sum(score) from Student left Outer join SC on Student.S#=SC.S# group by Student.S#,Sname 4、查询的老师的个数; select count(distinct(Tname)) from T 5、查询没学过“teacher3”老师课的同学的学号、姓名; Student.S#,Student.Sname from Student where S# not in (select distinct( SC.S#) from SC,Course,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='teacher3'); 6、查询学过“11”并且也学过编号“13”课程的同学的学号、姓名; select Student.S#,Student.Sname from Student,SC where Student.S#=SC.S# and SC.C#='11'and exists( Select * from SC as SC_2 where SC_2.S#=SC.S# and SC_2.C#='13'); 7、查询学过“teacher5”老师所教的所有课的同学的学号、姓名; select S#,Sname from Student where S# in (select S# from SC ,Course ,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='teacher5' group by S# having count(SC.C#)=(select count(C#) from Course,Teacher where Teacher.T#=Course.T# and Tname='teacher5')); 8、查询课程编号“14”的成绩比课程编号“11”课程低的所有同学的学号、姓名; Select S#,Sname from (select Student.S#,Student.Sname,score ,(select score from SC SC_2 where SC_2.S#=Student.S# and SC_2.C#='14') score2 from Student,SC where Student.S#=SC.S# and C#='11') S_2 where score2 & 9、查询所有课程成绩小于 60 分的同学的学号、姓名; select S#,Sname from Student where S# not in (select Student.S# from Student,SC where S.S#=SC.S# and score&60); 10、查询没有学全所有课的同学的学号、姓名; select Student.S#,Student.Sname from Student,SC where Student.S#=SC.S# group by Student.S#,Student.Sname having count(C#) &(select count(C#) from Course); 11、查询至少有一门课与学号为“110”的同学所学相同的同学的学号和姓名; select S#,Sname from Student,SC where Student.S#=SC.S# and C# in select C# from SC where S#='110'; 12、查询至少学过学号为“111”同学所有一门课的其他同学学号和姓名; select distinct SC.S#,Sname from Student,SC where Student.S#=SC.S# and C# in (select C# from SC where S#='111'); 13、把“SC”表中“teacher3”老师教的课的成绩都更改为此课程的平均成绩; update SC set score=(select avg(SC_2.score) from SC SC_2 where SC_2.C#=SC.C# ) from Course,Teacher where Course.C#=SC.C# and Course.T#=Teacher.T# and Teacher.Tname='teacher3'); 14、查询和“113”号的同学学习的课程完全相同的其他同学学号和姓名; select S# from SC where C# in (select C# from SC where S#='1002') group by S# having count(*)=(select count(*) from SC where S#='1002'); 15、删除学习“teacher3”老师课的 SC 表记录; Delect SC from course ,Teacher where Course.C#=SC.C# and Course.T#= Teacher.T# and Tname='teacher3'; 16、按平均成绩从高到低显示所有学生的“science”、“english”、“physical”三门的课程成绩, 按如下形式显示: 学生 ID,,science,english,physical,有效课程数,有效平均分 SELECT S# as 学生 ID ,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='11') AS science ,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='14') AS english ,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='16') AS physical ,COUNT(*) AS 有效课程数, AVG(t.score) AS 平均成绩 FROM SC AS t GROUP BY S# ORDER BY avg(t.score) 17、查询各科成绩最高和最低的分:以如下形式显示:课程 ID,最高分,最低分 SELECT L.C# As 课程 ID,L.score AS 最高分,R.score AS 最低分 FROM SC L ,SC AS R WHERE L.C# = R.C# and L.score = (SELECT MAX(IL.score) FROM SC AS IL,Student AS IM WHERE L.C# = IL.C# and IM.S#=IL.S# GROUP BY IL.C#) AND R.Score = (SELECT MIN(IR.score) FROM SC AS IR WHERE R.C# = IR.C# GROUP BY IR.C# ); 18、按各科平均成绩从低到高和及格率的百分数从高到低顺序 SELECT t.C# AS 课程号,ame)AS 课程名,isnull(AVG(score),0) AS 平均成 绩 ,100 * SUM(CASE WHEN isnull(score,0)&=60 THEN 1 ELSE 0 END)/COUNT(*) AS 及 格百分数 FROM SC T,Course where t.C#=course.C# GROUP BY t.C# ORDER BY 100 * SUM(CASE WHEN isnull(score,0)&=60 THEN 1 ELSE 0 END)/COUNT(*) DESC 19、查询不同老师所教不同课程平均分从高到低显示 SELECT max(Z.T#) AS 教 师 ID,MAX(Z.Tname) AS 教 师 姓 名 ,C.C# AS 课 程 I D,ame) AS 课程名称,AVG(Score) AS 平均成绩 FROM SC AS T,Course AS C ,Teacher AS Z where T.C#=C.C# and C.T#=Z.T# GROUP BY C.C# ORDER BY AVG(Score) DESC 20、查询如下课程成绩第 3 名到第 6 名的学生成绩单:math(10) ,article(12) ,physical ,english(14) (16) [学生 ID],[学生姓名],math,article,physical,english,平均成绩 SELECT DISTINCT top 3 SC.S# As 学生学号, Student.Sname AS 学生姓名 , T1.score AS math, T2.score AS article, T3.score AS physical , T4.score AS english, ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) as 总分 FROM Student,SC LEFT JOIN SC AS T1 ON SC.S# = T1.S# AND T1.C# = '001' LEFT JOIN SC AS T2 ON SC.S# = T2.S# AND T2.C# = '002' LEFT JOIN SC AS T3 ON SC.S# =T3.S# AND T3.C# = '003' LEFT JOIN SC AS T4 ON SC.S# = T4.S# AND T4.C# = '004' WHERE student.S#=SC.S# and ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) NOT IN (SELECT DISTINCT TOP 15 WITH TIES ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) FROM sc LEFT JOIN sc AS T1 ON sc.S# = T1.S# AND T1.C#= 'k1' LEFT JOIN sc AS T2 ON sc.S# = T2.S# AND T2.C# = 'k2' LEFT JOIN sc AS T3 ON sc.S# = T3.S# AND T3.C# = 'k3' LEFT JOIN sc AS T4 ON sc.S# = T4.S# AND T4.C# = 'k4' ORDER BY ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) DESC); 21、统计列印各科成绩,各分数段人数:课程 ID,课程名称,[100-85],[85-70],[70-60],[ &60] SELECT SC.C# as 课程 ID, Cname as 课程名称 ,SUM(CASE WHEN score BETWEEN 85 AND 100 THEN 1 ELSE 0 END) AS [100 - 85] ,SUM(CASE WHEN score BETWEEN 70 AND 85 THEN 1 ELSE 0 END) AS [85 - 70] ,SUM(CASE WHEN score BETWEEN 60 AND 70 THEN 1 ELSE 0 END) AS [70 - 60] ,SUM(CASE WHEN score & 60 THEN 1 ELSE 0 END) AS [60 -] FROM SC,Coursewhere SC.C#=Course.C# GROUP BY SC.C#,C 22、查询学生平均成绩及其名次 SELECT 1+(SELECT COUNT( distinct 平均成绩) FROM (SELECT S#,AVG(score) AS 平均成绩 FROM SC GROUP BY S# ) AS T1 WHERE 平均成绩 & T2.平均成绩) as 名次, S# as 学生学号,平均成绩 FROM (SELECT S#,AVG(score) 平均成绩 FROM SC GROUP BY S# ) AS T2 ORDER BY 平均成绩 23、查询各科成绩前三名的记录:(不考虑成绩并列情况) SELECT t1.S# as 学生 ID,t1.C# as 课程 ID,Score as 分数 FROM SC t1 WHERE score IN (SELECT TOP 3 score FROM SC WHERE t1.C#= C# ORDER BY score DESC ) ORDER BY t1.C#; 24、查询每门课程被选修的学生数 select c#,count(S#) from sc group by C#; 25、查询出只选修了一门课程的全部学生的学号和姓名 select SC.S#,Student.Sname,count(C#) AS 选课数 from SC ,Student where SC.S#=Student.S# group by SC.S# ,Student.Sname having count(C#)=1; 26、查询男生、女生人数 Select count(Ssex) as 男生人数 from Student group by Ssex having Ssex='1'; Select count(Ssex) as 女生人数 from Student group by Ssex having Ssex='0'; 27、查询含有的学生名单 SELECT Sname FROM Student WHERE Sname like 'to%'; 28、查询同名同性学生名单,并统计同名人数 select Sname,count(*) from Student group by Sname having count(*)&1;; 29、查询每门课程的平均成绩,结果按平均成绩升序排列,平均成绩相同时,按课程号降序 排列 Select C#,Avg(score) from SC group by C# order by Avg(score),C# DESC ; 30、查询平均成绩大于 85 的所有学生的学号、姓名和平均成绩 select Sname,SC.S# ,avg(score) from Student,SC where Student.S#=SC.S# group by SC.S#,Sname having avg(score)&85; 31、查询课程名称为“chemical”,且分数低于 60 的学生姓名和分数 Select Sname,isnull(score,0) from Student,SC,Course where SC.S#=Student.S# and SC.C#=Course.C#ame='chemical'and score &60; 32、查询所有学生的选课情况; SELECT SC.S#,SC.C#,Sname,Cname FROM SC,Student,Course where SC.S#=Student.S# and SC.C#=Course.C# ; 33、查询任何一门课程成绩在 70 分以上的姓名、课程名称和分数; SELECT distinct student.S#,student.Sname,SC.C#,SC.score FROM student,Sc WHERE SC.score&=70 AND SC.S#=student.S#; 34、查询不及格的课程,并按课程号从大到小排列 select c# from sc where scor e &60 order by C# ; 35、查询课程编号为 13 且课程成绩在 80 分以上的学生的学号和姓名; select SC.S#,Student.Sname from SC,Student where SC.S#=Student.S# and Score&80 and C#='003'; 36、求选了课程的学生人数 select count(*) 37、查询选修“teacher5”老师所授课程的学生中,成绩最高的学生姓名及其成绩 select Student.Sname,score from Student,SC,Course C,Teacher where Student.S#=SC.S# and SC.C#=C.C# and C.T#=Teacher.T# and Teacher.Tname='teacher5' and SC.score=(select max(score)from SC where C#=C.C# ); 38、查询各个课程及相应的选修人数 select count(*) from sc group by C#; 39、查询不同课程成绩相同的学生的学号、课程号、学生成绩 select distinct A.S#,B.score from SC A ,SC B where A.Score=B.Score and A.C# &&B.C# ; 40、查询每门功成绩最好的前两名 SELECT t1.S# as 学生 ID,t1.C# as 课程 ID,Score as 分数 FROM SC t1 WHERE score IN (SELECT TOP 2 score FROM SC WHERE t1.C#= C# ORDER BY score DESC ) ORDER BY t1.C#; 41、 统计每门课程的学生选修人数 (超过 10 人的课程才统计) 要求输出课程号和选修人数, 。 查询结果按人数降序排列,查询结果按人数降序排列,若人数相同,按课程号升序排列 select C# as 课程号,count(*) as 人数 from sc group by C# order by count(*) desc,c# 42、检索至少选修两门课程的学生学号 select S# from sc group by s# having count(*) & = 2 43、查询全部学生都选修的课程的课程号和课程名 select C#,Cname from Course where C# in (select c# from sc group by c#) 44、查询没学过“teacher2”老师讲授的任一门课程的学生姓名 select Sname from Student where S# not in (select S# from Course,Teacher,SC where Course.T#=Teacher.T# and SC.C#=course.C# and Tname='teacher2'); 45、查询两门以上不及格课程的同学的学号及其平均成绩 select S#,avg(isnull(score,0)) from SC where S# in (select S# from SC where score &60 group by S# having count(*)&2)group by S#; 46、检索“11”课程分数小于 60,按分数降序排列的同学学号 select S# from SC where C#='11'and score &60 47、删除“102”同学的“104”课程的成绩 delete from Sc where S#='102'and C#='104';
数据库SQL查询语句练习题_电脑基础知识_IT/计算机_专业资料。设教学数据库 Education 有三个关系: 学生关系 S(SNO,SNAME,AGE,SEX,SDEPT) ;学习关系 SC(SNO,CNO...练习 SQL 查询语句――基础的 select 格式: select 字段名 from 表名 1、写出查找 student 表中所有字段的语句,并在命令窗口测试 2、写出查找 student 表中学号...sql查询语句练习_计算机软件及应用_IT/计算机_专业资料。1、 查询Student表中的所有记录的Sname、Ssex和Class列。 2、 查询教师所有的单位即不重复的Depart列。 3...SQL查询语句练习习题 2页 免费如要投诉违规内容,请到百度文库投诉中心;如要提出功能问题或意见建议,请点击此处进行反馈。 数据库sql查询语句练习2_习题_结果(单世民...SQL 查询语句 课堂练习和习题一、试用 SQL 查询语句表达下列对教学数据库中三个基本 表 S、SC、C 的查询: S(sno,sname,SAGE,SSEX) 各字段表示学号,姓名,...数据库sql查询语句练习2_习题_结果(单世民)_IT认证_资格考试/认证_教育专区。现在有一教学管理系统,具体的关系模式如下: Student (no, name, sex, birthday, ...数据库SQL查询语句练习题_IT认证_资格考试/认证_教育专区。设教学数据库 Education 有三个关系: 学生关系 S(SNO,SNAME,AGE,SEX,SDEPT) ;学习关系 SC(SNO, CNO...数据库SQL查询语句练习题(1)_IT认证_资格考试/认证_教育专区。设教学数据库 Education 有三个关系: 学生关系 S(SNO,SNAME,AGE,SEX,SDEPT) ;学习关系 SC(SNO,...数据库SQL查询语句练习题_职高对口_职业教育_教育专区。设教学数据库 Education 有三个关系: 学生关系 S(SNO(学号),SNAME(姓名),AGE(年龄),SEX(性别),SDEPT(...sql 查询语句练习(解析版) BY DD 查询语句练习(解析版) 表情况 Student(S#,Sname,Sage,Ssex) 学生表 Course(C#,Cname,T#) 课程表 SC(S#,C#,score) ...
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