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时间:2016-11-18 11:41
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有些路只能一个人走
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{if lbtxtwidth>12}
{if !!labs.icon}
{list photos as photo}
{if photo_index==0}{break}{/if}
品牌${make||'-'}
型号${model||'-'}
焦距${focalLength||'-'}
光圈${apertureValue||'-'}
快门速度${exposureTime||'-'}
ISO${isoSpeedRatings||'-'}
曝光补偿${exposureBiasValue||'-'}
镜头${lens||'-'}
{if data.msgRank == 1}{/if}
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{if defined('posts')&&posts.length>0}
{list posts as post}
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{if post.type == 1 || post.type == 5}
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{if post.type == 2}
{if post.type == 3}
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{list drlist as dr}{if drlist.length === 3 && dr_index === 0}、{/if}{if drlist.length === 3 && dr_index === 1}、{/if}{if drlist.length === 2 && dr_index === 0}、{/if}{/list}
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{if defined('posts')&&posts.length>0}
{list posts as post}
{if post.type == 2}
{if post.type == 3}
{if post.type == 4}
this.p={ dwrMethod:'queryLikePosts',fpost:'1d0abced_a550e68',userId:,blogListLength:6};智力题,一个人上台阶的方式有三种,一次跨1、2、3步,那么他要上25步台阶的方法有多少种.
梦风儿1343
设所走的台阶数为A.当A=1时,只有一种走法,走1阶,也就是a(1)=1当A=2时,有两种,走两个1阶和1个两阶,a(2)=2当A=3时,有1+1+1,1+2,2+1,3四种,a(3)=4当A>3时,因为最后一步可以跨1阶、跨2阶、跨3阶,所以总走法就是a(A)=a(A-1)+a(A-2)+a(A-3)台阶数 走的方法1 12 23 44 75 136 247 448 819 14910 27411 50412 92713 170514 313615 576816 1060917 1951318 3589019 6601220 12141521 22331722 41074423 75547624 138953725 2555757
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