已知f(x),求f(2x)–f(x–1)=3.f(f(x))=3.求f(x)

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f(x–1)=f(3–x)的函数图象的对称轴方程为?已知f(x)=ax2+bx,为什么f(x–1)=f(3–x)知此函数图象的对称轴方程为x=–b/2a =-1或者x=1怎么得来的
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对称轴是X=1,你是想知道简单算法还是复杂的?简单的[(3–x)+(x–1)]/2就可以了``复杂的`我懒得打字
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用罗尔定理证明f(x)=(x–1)(x–2)(x–3)的导数有几个实根,并指出根的范围
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f(x)=(x–1)(x–2)(x–3)有3根1,2,3用罗尔定理:f'(x)在(1,2) (2,3)各有1根.
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